Matura (sierpień 2023, poziom podstawowy, poprawka, Formuła 2015)

$\displaystyle \left(- \frac{1}{4} \right)$\displaystyle \left(- \frac{1}{4} \right)

$\displaystyle \left(- \frac{1}{2} \right)$\displaystyle \left(- \frac{1}{2} \right)

$\displaystyle \left( \frac{1}{4} \right)$\displaystyle \left( \frac{1}{4} \right)

$\displaystyle \frac{1}{2}$\displaystyle \frac{1}{2}

$\displaystyle \left(7 \cdot 5\right)^{ \frac{1}{2} }$\displaystyle \left(7 \cdot 5\right)^{ \frac{1}{2} }

$\displaystyle 5^{ \frac{1}{2} }$\displaystyle 5^{ \frac{1}{2} }

$7$7

$\displaystyle 7 \cdot 5^{ \frac{1}{2} }$\displaystyle 7 \cdot 5^{ \frac{1}{2} }

$\displaystyle 16\frac{2}{3}\%$\displaystyle 16\frac{2}{3}\% jego początkowej wartości.

$\displaystyle 20\%$\displaystyle 20\% jego początkowej wartości.

$\displaystyle 40\%$\displaystyle 40\% jego początkowej wartości.

$\displaystyle 83\frac{1}{3}\%$\displaystyle 83\frac{1}{3}\% jego początkowej wartości.

$\displaystyle \frac{1}{3}$\displaystyle \frac{1}{3}

$\displaystyle \left( -\frac{1}{3} \right)$\displaystyle \left( -\frac{1}{3} \right)

$3$3

$\left(-3\right)$\left(-3\right)

$\left(-2\sqrt{3}\right)$\left(-2\sqrt{3}\right)

$0$0

$6$6

$8\sqrt{3}$8\sqrt{3}

$2𝑥 + 3𝑦 = 2$2𝑥 + 3𝑦 = 2 i $−𝑥 + 𝑦 = −14$−𝑥 + 𝑦 = −14

$3𝑥 + 2𝑦 = −12$3𝑥 + 2𝑦 = −12 i $2𝑥 + 𝑦 = 10$2𝑥 + 𝑦 = 10

$𝑥 + 𝑦 = −2$𝑥 + 𝑦 = −2 i $𝑥 − 2𝑦 = 4$𝑥 − 2𝑦 = 4

$𝑥 − 𝑦 = −14$𝑥 − 𝑦 = −14 i $−2𝑥 + 𝑦 = 22$−2𝑥 + 𝑦 = 22

$\displaystyle \left(-\infty, \frac{2}{3} \right]$\displaystyle \left(-\infty, \frac{2}{3} \right]

$\displaystyle \left(-\infty,- \frac{2}{3} \right]$\displaystyle \left(-\infty,- \frac{2}{3} \right]

$\displaystyle \left[ \frac{2}{3},\infty \right)$\displaystyle \left[ \frac{2}{3},\infty \right)

$\displaystyle \left[- \frac{2}{3},\infty \right)$\displaystyle \left[- \frac{2}{3},\infty \right)

jedno rozwiązanie.

dwa rozwiązania.

trzy rozwiązania.

cztery rozwiązania.

$\left(-3\right)$\left(-3\right)

$3$3

$\left(-4\right)$\left(-4\right)

$4$4

$\displaystyle f(x)=- \frac{1}{2}x+1$\displaystyle f(x)=- \frac{1}{2}x+1

$\displaystyle f(x)=- \frac{1}{3}x+ \frac{1}{3}$\displaystyle f(x)=- \frac{1}{3}x+ \frac{1}{3}

$f(x)=-2x+2$f(x)=-2x+2

$f(x)=-3x+1$f(x)=-3x+1

$\left(-29\right)$\left(-29\right)

$\left(-23\right)$\left(-23\right)

$23$23

$29$29

$\left[-1,4\right]$\left[-1,4\right]

$\left[5,7\right]$\left[5,7\right]

$\left[-8,-6\right]$\left[-8,-6\right]

$\left[1,6\right]$\left[1,6\right]

$A$A

$B$B

$C$C

$D$D

najmniejszą równą $3$3.

najmniejszą równą $4$4.

największą równą $3$3.

największą równą $4$4.

$2$2

$\left(-2\right)$\left(-2\right)

$3$3

$\left(-1\right)$\left(-1\right)

$\displaystyle \left(- \frac{5}{4} \right)$\displaystyle \left(- \frac{5}{4} \right)

$\left(-4\right)$\left(-4\right)

$\displaystyle \left(- \frac{1}{4} \right)$\displaystyle \left(- \frac{1}{4} \right)

$\displaystyle \left(- \frac{15}{4} \right)$\displaystyle \left(- \frac{15}{4} \right)

$\displaystyle \frac{3}{4}\pi$\displaystyle \frac{3}{4}\pi

$\displaystyle \frac{1}{2}\pi$\displaystyle \frac{1}{2}\pi

$\displaystyle \frac{3}{4}\pi +6$\displaystyle \frac{3}{4}\pi +6

$\displaystyle \frac{1}{2}\pi+6$\displaystyle \frac{1}{2}\pi+6

$\displaystyle \frac{24}{49}$\displaystyle \frac{24}{49}

$\displaystyle \frac{5}{7}$\displaystyle \frac{5}{7}

$\displaystyle \frac{25}{49}$\displaystyle \frac{25}{49}

$\displaystyle \frac{\sqrt{6}}{7}$\displaystyle \frac{\sqrt{6}}{7}

$40^\circ$40^\circ

$80^\circ$80^\circ

$100^\circ$100^\circ

$120^\circ$120^\circ

$\displaystyle \frac{3\sqrt{3}}{4}$\displaystyle \frac{3\sqrt{3}}{4}

$\displaystyle \frac{9\sqrt{3}}{4}$\displaystyle \frac{9\sqrt{3}}{4}

$3\sqrt{3}$3\sqrt{3}

$6\sqrt{3}$6\sqrt{3}

$120^\circ$120^\circ

$135^\circ$135^\circ

$144^\circ$144^\circ

$150^\circ$150^\circ

$\displaystyle \frac{3}{4}L$\displaystyle \frac{3}{4}L

$\displaystyle \frac{3}{7}L$\displaystyle \frac{3}{7}L

$\displaystyle \frac{4}{7}L$\displaystyle \frac{4}{7}L

$\displaystyle \frac{1}{4}L$\displaystyle \frac{1}{4}L

$\displaystyle y=- \frac{3}{4}x+8$\displaystyle y=- \frac{3}{4}x+8

$\displaystyle y= \frac{3}{4}x-10$\displaystyle y= \frac{3}{4}x-10

$\displaystyle y= \frac{4}{3}x-17$\displaystyle y= \frac{4}{3}x-17

$\displaystyle y=- \frac{4}{3}x+15$\displaystyle y=- \frac{4}{3}x+15

$\sqrt{5}$\sqrt{5}

$2\sqrt{5}$2\sqrt{5}

$3\sqrt{5}$3\sqrt{5}

$6\sqrt{5}$6\sqrt{5}

$216+18\sqrt{3}$216+18\sqrt{3}

$216+54\sqrt{3}$216+54\sqrt{3}

$216+216\sqrt{3}$216+216\sqrt{3}

$216+108\sqrt{3}$216+108\sqrt{3}

$\displaystyle \frac{1}{2}$\displaystyle \frac{1}{2}

$\displaystyle \frac{2}{\sqrt{5}}$\displaystyle \frac{2}{\sqrt{5}}

$\displaystyle \frac{1}{\sqrt{5}}$\displaystyle \frac{1}{\sqrt{5}}

$\displaystyle \frac{\sqrt{3}}{2}$\displaystyle \frac{\sqrt{3}}{2}

$24$24

$3$3

$6$6

$4$4

$5\ 690\ \text{zł}$5\ 690\ \text{zł}

$5\ 280\ \text{zł}$5\ 280\ \text{zł}

$6\ 257\ \text{zł}$6\ 257\ \text{zł}

$5\ 900\ \text{zł}$5\ 900\ \text{zł}

$9 \cdot 10 \cdot 10 \cdot 10 \cdot 10$9 \cdot 10 \cdot 10 \cdot 10 \cdot 10

$9 \cdot 9 \cdot 9 \cdot 9$9 \cdot 9 \cdot 9 \cdot 9

$10 \cdot 9 \cdot 8 \cdot 7$10 \cdot 9 \cdot 8 \cdot 7

$9 \cdot 9 \cdot 8 \cdot 7$9 \cdot 9 \cdot 8 \cdot 7