punkt-sleft27right-jest-srodkiem-odcinka-ab-w-ktorym-aleft-13right-punkt

$B=\left(5,11\right)$B=\left(5,11\right)

$\displaystyle B=\left( \frac{1}{2},2 \right)$\displaystyle B=\left( \frac{1}{2},2 \right)

$B=\displaystyle \left( -\frac{3}{2},-5\right)$B=\displaystyle \left( -\frac{3}{2},-5\right)

$B=\left(3,11\right)$B=\left(3,11\right)