Kąt jest ostry i . Wtedy
tgα=34\displaystyle \tg\alpha= \frac{3}{4} tgα=43\displaystyle \tg\alpha= \frac{3}{4}
tgα=45\displaystyle \tg\alpha= \frac{4}{5} tgα=54\displaystyle \tg\alpha= \frac{4}{5}
sinα=15\displaystyle \sin\alpha= \frac{1}{5 } sinα=51\displaystyle \sin\alpha= \frac{1}{5 }
sinα=45\displaystyle \sin\alpha= \frac{4}{5} sinα=54\displaystyle \sin\alpha= \frac{4}{5}
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