Kąt jest ostry i . Wtedy
\displaystyle \sin\alpha= \frac{12}{13} oraz \displaystyle \tg\alpha= \frac{12}{5}
\displaystyle \sin\alpha= \frac{12}{13} oraz \displaystyle \tg\alpha= \frac{5}{12}
\displaystyle \sin\alpha= \frac{12}{5} oraz \displaystyle \tg\alpha= \frac{12}{13}
\displaystyle \sin\alpha= \frac{5}{12} oraz \displaystyle \tg\alpha= \frac{12}{13}
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