O zdarzeniu losowym , zawartym w wiemy, że . Wtedy
P(A)=0,16P\left(A\right)=0{,}16P(A)=0,16P\left(A\right)=0{,}16
P(A)=0,328P\left(A\right)=0{,}328P(A)=0,328P\left(A\right)=0{,}328
P(A)=0,84P\left(A\right)=0{,}84P(A)=0,84P\left(A\right)=0{,}84
P(A)=0,94P\left(A\right)=0{,}94P(A)=0,94P\left(A\right)=0{,}94
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