Wiadomo, że i . Wtedy liczba jest równa
3a+1a+b\displaystyle \frac{3a+1}{a+b} a+b3a+1\displaystyle \frac{3a+1}{a+b}
2a+1a+b\displaystyle \frac{2a+1}{a+b} a+b2a+1\displaystyle \frac{2a+1}{a+b}
2a+1a+2b\displaystyle \frac{2a+1}{a+2b} a+2b2a+1\displaystyle \frac{2a+1}{a+2b}
3a+12b+a\displaystyle \frac{3a+1}{2b+a} 2b+a3a+1\displaystyle \frac{3a+1}{2b+a}
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