$|x+1|>5$|x+1|>5

$|x-1|<2$|x-1|<2

$\displaystyle \left| x+ \frac{2}{3}\right|\le 4$\displaystyle \left| x+ \frac{2}{3}\right|\le 4

$\displaystyle \left| x- \frac{1}{3}\right|\ge 3$\displaystyle \left| x- \frac{1}{3}\right|\ge 3