pierwiastki-x1x2-rownania-2x2x-20-spelniaja-warunek

$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}=-1$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}=-1

$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}=0$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}=0

$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}= \frac{1}{4}$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}= \frac{1}{4}

$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}= \frac{1}{2}$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}= \frac{1}{2}