Matura (maj 2014, poziom podstawowy)

$\begin{cases} \displaystyle y=x+1\\ y=-2x+4 \end{cases}$\begin{cases} \displaystyle y=x+1\\ y=-2x+4 \end{cases}

$\begin{cases} \displaystyle y=x-1\\ y=2x+4 \end{cases}$\begin{cases} \displaystyle y=x-1\\ y=2x+4 \end{cases}

$\begin{cases} \displaystyle y=x-1\\ y=-2x+4 \end{cases}$\begin{cases} \displaystyle y=x-1\\ y=-2x+4 \end{cases}

$\begin{cases} \displaystyle y=x+1\\ y=2x+4 \end{cases}$\begin{cases} \displaystyle y=x+1\\ y=2x+4 \end{cases}

$c=60$c=60

$c=52$c=52

$c=48$c=48

$c=39$c=39

$-2$-2

$-2\sqrt{3}$-2\sqrt{3}

$2$2

$2\sqrt{3}$2\sqrt{3}

$3$3

$\displaystyle \frac{3}{2}$\displaystyle \frac{3}{2}

$\displaystyle \log_{8}{17}$\displaystyle \log_{8}{17}

$\displaystyle \frac{7}{3}$\displaystyle \frac{7}{3}

$-1$-1

$1$1

$5$5

$10$10

$m\in\{-2,2\}$m\in\{-2,2\}

$m\in\left(-2,2\right)$m\in\left(-2,2\right)

$m\in\left(-\infty,-2\right)$m\in\left(-\infty,-2\right)

$m\in\left(2,+\infty\right)$m\in\left(2,+\infty\right)

$\displaystyle f(x)= \frac{1}{2}(x+3)(x-1)$\displaystyle f(x)= \frac{1}{2}(x+3)(x-1)

$\displaystyle f(x)= \frac{1}{2}(x-3)(x+1)$\displaystyle f(x)= \frac{1}{2}(x-3)(x+1)

$\displaystyle f(x)= -\frac{1}{2}(x+3)(x-1)$\displaystyle f(x)= -\frac{1}{2}(x+3)(x-1)

$\displaystyle f(x)= -\frac{1}{2}(x-3)(x+1)$\displaystyle f(x)= -\frac{1}{2}(x-3)(x+1)

$\displaystyle y= \frac{1}{2}x+2$\displaystyle y= \frac{1}{2}x+2

$y=-2x+2$y=-2x+2

$\displaystyle y=- \frac{1}{2}x+2$\displaystyle y=- \frac{1}{2}x+2

$y=2x+2$y=2x+2

$2$2

$3$3

$\displaystyle -\frac{6}{x}$\displaystyle -\frac{6}{x}

$\displaystyle \frac{6}{x}$\displaystyle \frac{6}{x}

$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}=-1$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}=-1

$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}=0$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}=0

$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}= \frac{1}{4}$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}= \frac{1}{4}

$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}= \frac{1}{2}$\displaystyle \frac{1}{x_1}+ \frac{1}{x_2}= \frac{1}{2}

$a_n=-3n+5$a_n=-3n+5

$a_n=n-3$a_n=n-3

$a_n=-n+3$a_n=-n+3

$a_n=3n-5$a_n=3n-5

$2$2

$\displaystyle \frac{1}{2}$\displaystyle \frac{1}{2}

$\sqrt{2}$\sqrt{2}

$\displaystyle \frac{\sqrt{2}}{2}$\displaystyle \frac{\sqrt{2}}{2}

$0$0

$2$2

$3$3

$5$5

$\displaystyle - \frac{11}{23}$\displaystyle - \frac{11}{23}

$\displaystyle \frac{24}{5}$\displaystyle \frac{24}{5}

$\displaystyle - \frac{23}{11}$\displaystyle - \frac{23}{11}

$\displaystyle \frac{5}{24}$\displaystyle \frac{5}{24}

$0$0

$1$1

$2$2

$4$4

$\sqrt{3}$\sqrt{3}

$3$3

$2\sqrt{3}$2\sqrt{3}

$2$2

$160^\circ$160^\circ

$80^\circ$80^\circ

$40^\circ$40^\circ

$20^\circ$20^\circ

$\displaystyle f(x)=- \frac{1}{3}x+ \frac{7}{3}$\displaystyle f(x)=- \frac{1}{3}x+ \frac{7}{3}

$\displaystyle f(x)=- \frac{1}{2}x+2$\displaystyle f(x)=- \frac{1}{2}x+2

$f(x)=-3x+7$f(x)=-3x+7

$f(x)=-2x+4$f(x)=-2x+4

$5$5

$7$7

$8$8

$10$10

sześć razy dłuższa od wysokości walca.

trzy razy dłuższa od wysokości walca.

dwa razy dłuższa od wysokości walca.

równa wysokości walca.

$\displaystyle \frac{1}{225}$\displaystyle \frac{1}{225}

$\displaystyle \frac{1}{15}$\displaystyle \frac{1}{15}

$1$1

$15$15

$A=\left(1,-2\right)$A=\left(1,-2\right)

$B=\left(2,-1\right)$B=\left(2,-1\right)

$\displaystyle C=\left(1, \frac{1}{2} \right)$\displaystyle C=\left(1, \frac{1}{2} \right)

$D=\left(4,4\right)$D=\left(4,4\right)

$\displaystyle P(A)= \frac{2}{3}$\displaystyle P(A)= \frac{2}{3}

$\displaystyle P(A)= \frac{1}{2}$\displaystyle P(A)= \frac{1}{2}

$\displaystyle P(A)= \frac{1}{3}$\displaystyle P(A)= \frac{1}{3}

$\displaystyle P(A)= \frac{1}{6}$\displaystyle P(A)= \frac{1}{6}

$100$100

$90$90

$45$45

$20$20

$a=4$a=4

$a=6$a=6

$a=7$a=7

$a=9$a=9