na-rysunku-zaznaczono-dlugosci-bokow-i-kat-alpha-trojkata-prostokatnego

$\displaystyle \cos\alpha= \frac{5}{13}$\displaystyle \cos\alpha= \frac{5}{13}

$\displaystyle \tg\alpha= \frac{13}{12 }$\displaystyle \tg\alpha= \frac{13}{12 }

$\cos\alpha= \frac{12}{13}$\cos\alpha= \frac{12}{13}

$\displaystyle \tg\alpha= \frac{12}{5}$\displaystyle \tg\alpha= \frac{12}{5}