w-kartezjanskim-ukladzie-wspolrzednych-przedstawiono-fragment-wykresu-funkcji-4

$\displaystyle \displaystyle f(x)= \frac{1}{2}(x-2)(x-6)$\displaystyle \displaystyle f(x)= \frac{1}{2}(x-2)(x-6)

$\displaystyle \displaystyle f(x)= \frac{1}{2}(x-4)^2-2$\displaystyle \displaystyle f(x)= \frac{1}{2}(x-4)^2-2

$\displaystyle 𝑓(𝑥) = 2(𝑥 − 2)(𝑥 − 6)$\displaystyle 𝑓(𝑥) = 2(𝑥 − 2)(𝑥 − 6)

$\displaystyle f(x)= \frac{1}{2}(x+4)^2-2$\displaystyle f(x)= \frac{1}{2}(x+4)^2-2

$f(x)=2(x+2)(x+6)$f(x)=2(x+2)(x+6)

$\displaystyle f(x)= 2(x+4)^2-2$\displaystyle f(x)= 2(x+4)^2-2