jezeli-displaystyle-cosbeta-frac13-i-displaystyle-betainleftpi-frac32pi-right-to

$\displaystyle \frac{-2\sqrt{2}+\sqrt{3}}{6}$\displaystyle \frac{-2\sqrt{2}+\sqrt{3}}{6}

$\displaystyle \frac{2\sqrt{6}+1}{6}$\displaystyle \frac{2\sqrt{6}+1}{6}

$\displaystyle \frac{2\sqrt{2}+\sqrt{3}}{6}$\displaystyle \frac{2\sqrt{2}+\sqrt{3}}{6}

$\displaystyle \frac{1-2\sqrt{6}}{6}$\displaystyle \frac{1-2\sqrt{6}}{6}