rownanie-left2x-1right-cdot-leftx-2rightleft1-2xright-cdot-leftx2right-ma-dwa-rozwiazania-sa

$-2$-2 oraz $\displaystyle \frac{1}{2}$\displaystyle \frac{1}{2}

$0$0 oraz $\displaystyle \frac{1}{2}$\displaystyle \frac{1}{2}

$\displaystyle \frac{1}{2}$\displaystyle \frac{1}{2} oraz $2$2

$-2$-2 oraz $2$2