Kąt α jest ostry i cosα= 5/13. Wtedy

$\displaystyle \sin\alpha= \frac{12}{13}$\displaystyle \sin\alpha= \frac{12}{13} oraz $\displaystyle \tg\alpha= \frac{12}{5}$\displaystyle \tg\alpha= \frac{12}{5}

$\displaystyle \sin\alpha= \frac{12}{13}$\displaystyle \sin\alpha= \frac{12}{13} oraz $\displaystyle \tg\alpha= \frac{5}{12}$\displaystyle \tg\alpha= \frac{5}{12}

$\displaystyle \sin\alpha= \frac{12}{5}$\displaystyle \sin\alpha= \frac{12}{5} oraz $\displaystyle \tg\alpha= \frac{12}{13}$\displaystyle \tg\alpha= \frac{12}{13}

$\displaystyle \sin\alpha= \frac{5}{12}$\displaystyle \sin\alpha= \frac{5}{12} oraz $\displaystyle \tg\alpha= \frac{12}{13}$\displaystyle \tg\alpha= \frac{12}{13}