Matura (maj 2011, poziom podstawowy)

$|x+1|>5$|x+1|>5

$|x-1|<2$|x-1|<2

$\displaystyle \left| x+ \frac{2}{3}\right|\le 4$\displaystyle \left| x+ \frac{2}{3}\right|\le 4

$\displaystyle \left| x- \frac{1}{3}\right|\ge 3$\displaystyle \left| x- \frac{1}{3}\right|\ge 3

$1701$1701 zł

$2100$2100 zł

$1890$1890 zł

$2091$2091 zł

$5a^2(1-10b+3)$5a^2(1-10b+3)

$5a(a-2b+3)$5a(a-2b+3)

$5a(a-10b+15)$5a(a-10b+15)

$5(a-2b+3)$5(a-2b+3)

$a=-1$a=-1

$a=0$a=0

$a=2$a=2

$a=3$a=3

$\left(-\infty,3\right)$\left(-\infty,3\right)

$\left(10,+\infty\right)$\left(10,+\infty\right)

$\left(-5,-1\right)$\left(-5,-1\right)

$\left(2,+\infty\right)$\left(2,+\infty\right)

$1$1

$2$2

$-1$-1

$-2$-2

$A$A

$B$B

$C$C

$D$D

$\displaystyle x\le \frac{1}{2}$\displaystyle x\le \frac{1}{2}

$\displaystyle x> \frac{1}{2}$\displaystyle x> \frac{1}{2}

$x\le0$x\le0

$x>0$x>0

$A$A

$B$B

$C$C

$D$D

$-2\sqrt{2}$-2\sqrt{2}

$\displaystyle \frac{\sqrt{2}}{2}$\displaystyle \frac{\sqrt{2}}{2}

$\displaystyle - \frac{\sqrt{2}}{2}$\displaystyle - \frac{\sqrt{2}}{2}

$2\sqrt{2}$2\sqrt{2}

$\displaystyle a_1= \frac{2}{3}$\displaystyle a_1= \frac{2}{3}

$\displaystyle a_1= \frac{4}{9}$\displaystyle a_1= \frac{4}{9}

$\displaystyle a_1= \frac{3}{2}$\displaystyle a_1= \frac{3}{2}

$\displaystyle a_1= \frac{9}{4}$\displaystyle a_1= \frac{9}{4}

$a_4+a_7=a_{10}$a_4+a_7=a_{10}

$a_4+a_6=a_3+a_8$a_4+a_6=a_3+a_8

$a_2+a_9=a_3+a_8$a_2+a_9=a_3+a_8

$a_5+a_7=2a_8$a_5+a_7=2a_8

$\displaystyle \sin\alpha= \frac{12}{13}$\displaystyle \sin\alpha= \frac{12}{13} oraz $\displaystyle \tg\alpha= \frac{12}{5}$\displaystyle \tg\alpha= \frac{12}{5}

$\displaystyle \sin\alpha= \frac{12}{13}$\displaystyle \sin\alpha= \frac{12}{13} oraz $\displaystyle \tg\alpha= \frac{5}{12}$\displaystyle \tg\alpha= \frac{5}{12}

$\displaystyle \sin\alpha= \frac{12}{5}$\displaystyle \sin\alpha= \frac{12}{5} oraz $\displaystyle \tg\alpha= \frac{12}{13}$\displaystyle \tg\alpha= \frac{12}{13}

$\displaystyle \sin\alpha= \frac{5}{12}$\displaystyle \sin\alpha= \frac{5}{12} oraz $\displaystyle \tg\alpha= \frac{12}{13}$\displaystyle \tg\alpha= \frac{12}{13}

$\displaystyle \frac{1}{2}$\displaystyle \frac{1}{2}

$0$0

$\displaystyle - \frac{1}{2}$\displaystyle - \frac{1}{2}

$1$1

$AB$AB

$BG$BG

$GE$GE

$EB$EB

$80^\circ$80^\circ

$100^\circ$100^\circ

$110^\circ$110^\circ

$120^\circ$120^\circ

$3\sqrt{3}$3\sqrt{3}

$3$3

$6\sqrt{3}$6\sqrt{3}

$6$6

$y=-2x+3$y=-2x+3

$y=2x+1$y=2x+1

$y=2x+5$y=2x+5

$y=-x+1$y=-x+1

$x=1$x=1

$x=3$x=3

$y=0$y=0

$y=4$y=4

$\sqrt{6}$\sqrt{6}

$3$3

$9$9

$3\sqrt{3}$3\sqrt{3}

$124\pi$124\pi

$96\pi$96\pi

$64\pi$64\pi

$32\pi$32\pi

$\displaystyle \frac{1}{6}$\displaystyle \frac{1}{6}

$\displaystyle \frac{1}{9}$\displaystyle \frac{1}{9}

$\displaystyle \frac{1}{12}$\displaystyle \frac{1}{12}

$\displaystyle \frac{1}{18}$\displaystyle \frac{1}{18}

$3$3

$4$4

$5$5

$7$7