Matura (maj 2015, poziom podstawowy, (stara formuła))

$37\ 236\ \text{zł}$37\ 236\ \text{zł}

$39\ 842{,}52\ \text{zł}$39\ 842{,}52\ \text{zł}

$39\ 483\ \text{zł}$39\ 483\ \text{zł}

$42\ 246{,}81\ \text{zł}$42\ 246{,}81\ \text{zł}

$x=1$x=1

$x=2$x=2

$x=3$x=3

$x=6$x=6

$2^{ \frac{20}{3} }$2^{ \frac{20}{3} }

$2$2

$\displaystyle 2^{ \frac{4}{5} }$\displaystyle 2^{ \frac{4}{5} }

$2^3$2^3

$2$2

$\log_596$\log_596

$2\log_56$2\log_56

$5$5

$\displaystyle \left[ \frac{9}{15},+\infty \right)$\displaystyle \left[ \frac{9}{15},+\infty \right)

$\displaystyle \left(-\infty, \frac{18}{25} \right]$\displaystyle \left(-\infty, \frac{18}{25} \right]

$\displaystyle \left[ \frac{1}{30},+\infty \right)$\displaystyle \left[ \frac{1}{30},+\infty \right)

$\displaystyle \left(-\infty, \frac{9}{5} \right]$\displaystyle \left(-\infty, \frac{9}{5} \right]

wszystkich liczb rzeczywistych różnych od $0$0 i od $4$4.

wszystkich liczb rzeczywistych różnych od $-4$-4 i od $4$4.

wszystkich liczb rzeczywistych różnych od $-4$-4 i od $0$0.

wszystkich liczb rzeczywistych.

$x=0$x=0

$\displaystyle x= \frac{12}{5}$\displaystyle x= \frac{12}{5}

$x=2$x=2

$\displaystyle x= \frac{25}{11}$\displaystyle x= \frac{25}{11}

$0$0

$6$6

$4$4

$-6$-6

$\displaystyle a=- \frac{1}{2}$\displaystyle a=- \frac{1}{2}

$a=2$a=2

$\displaystyle a= \frac{1}{2}$\displaystyle a= \frac{1}{2}

$a=-2$a=-2

$\displaystyle a=- \frac{3}{2}$\displaystyle a=- \frac{3}{2}

$\displaystyle a=- \frac{2}{3}$\displaystyle a=- \frac{2}{3}

$\displaystyle a=- \frac{2}{5}$\displaystyle a=- \frac{2}{5}

$\displaystyle a=- \frac{3}{5}$\displaystyle a=- \frac{3}{5}

$81$81

$80$80

$76$76

$77$77

$\displaystyle q= \frac{1}{3}$\displaystyle q= \frac{1}{3}

$\displaystyle q= \frac{1}{\sqrt[3]{3}}$\displaystyle q= \frac{1}{\sqrt[3]{3}}

$q=\sqrt[3]{3}$q=\sqrt[3]{3}

$q=3$q=3

$0^\circ <\alpha<30^\circ$0^\circ <\alpha<30^\circ

$30^\circ <\alpha<45^\circ$30^\circ <\alpha<45^\circ

$45^\circ <\alpha<60^\circ$45^\circ <\alpha<60^\circ

$60^\circ <\alpha<90^\circ$60^\circ <\alpha<90^\circ

$\displaystyle \frac{5}{2}$\displaystyle \frac{5}{2}

$\displaystyle \frac{\sqrt{21}}{4}$\displaystyle \frac{\sqrt{21}}{4}

$\displaystyle \frac{3}{5}$\displaystyle \frac{3}{5}

$\displaystyle \frac{\sqrt{21}}{5}$\displaystyle \frac{\sqrt{21}}{5}

$10^\circ$10^\circ

$12{,}5^\circ$12{,}5^\circ

$13{,}5^\circ$13{,}5^\circ

$15^\circ$15^\circ

$a=13,b=17$a=13,b=17

$a=10,b=18$a=10,b=18

$a=9,b=19$a=9,b=19

$a=11,b=13$a=11,b=13

$\displaystyle m=- \frac{1}{2}$\displaystyle m=- \frac{1}{2}

$\displaystyle m= \frac{1}{2}$\displaystyle m= \frac{1}{2}

$m=1$m=1

$m=2$m=2

$y=-3x+4$y=-3x+4

$y=3x-4$y=3x-4

$\displaystyle y=- \frac{1}{3}x+4$\displaystyle y=- \frac{1}{3}x+4

$y=3x+4$y=3x+4

$1$1

$5$5

$5\sqrt{2}$5\sqrt{2}

$2\sqrt{5}$2\sqrt{5}

$S=\left(0,2\right)$S=\left(0,2\right)

$S=\left(-2,0\right)$S=\left(-2,0\right)

$S=\left(4,0\right)$S=\left(4,0\right)

$S=\left(0,4\right)$S=\left(0,4\right)

$\left(x+3\right)^2+\left(y+1\right)^2=18$\left(x+3\right)^2+\left(y+1\right)^2=18

$\left(x-3\right)^2+\left(y+1\right)^2=18$\left(x-3\right)^2+\left(y+1\right)^2=18

$\left(x-3\right)^2+\left(y-1\right)^2=18$\left(x-3\right)^2+\left(y-1\right)^2=18

$\left(x+3\right)^2+\left(y-1\right)^2=18$\left(x+3\right)^2+\left(y-1\right)^2=18

$24$24

$12\sqrt{2}$12\sqrt{2}

$12$12

$16\sqrt{2}$16\sqrt{2}

$\displaystyle \frac{25}{\pi}\ \text{cm}$\displaystyle \frac{25}{\pi}\ \text{cm}

$\displaystyle 10\ \text{cm}$\displaystyle 10\ \text{cm}

$\displaystyle \frac{10}{\pi}\ \text{cm}$\displaystyle \frac{10}{\pi}\ \text{cm}

$\displaystyle 5\ \text{cm}$\displaystyle 5\ \text{cm}

$x=0$x=0

$x=3$x=3

$x=5$x=5

$x=6$x=6

$\displaystyle \frac{4}{5}$\displaystyle \frac{4}{5}

$\displaystyle \frac{4}{9}$\displaystyle \frac{4}{9}

$\displaystyle \frac{1}{4}$\displaystyle \frac{1}{4}

$\displaystyle \frac{1}{9}$\displaystyle \frac{1}{9}