Kąt α jest ostry i tgα=√(2). Wtedy sinα jest równy

$\displaystyle \frac{\sqrt{2}}{2}$\displaystyle \frac{\sqrt{2}}{2}

$\displaystyle \frac{\sqrt{6}}{3}$\displaystyle \frac{\sqrt{6}}{3}

$\displaystyle \frac{\sqrt{3}}{2}$\displaystyle \frac{\sqrt{3}}{2}

$\displaystyle \frac{\sqrt{2}}{3}$\displaystyle \frac{\sqrt{2}}{3}