w-trojkacie-prostokatnym-dane-sa-dlugosci-bokow-zobacz-rysunek-wtedy

$\displaystyle \cos\alpha= \frac{9}{11}$\displaystyle \cos\alpha= \frac{9}{11}

$\displaystyle \sin\alpha= \frac{9}{11}$\displaystyle \sin\alpha= \frac{9}{11}

$\displaystyle \sin\alpha= \frac{11}{2\sqrt{10}}$\displaystyle \sin\alpha= \frac{11}{2\sqrt{10}}

$\displaystyle \cos\alpha= \frac{2\sqrt{10}}{11}$\displaystyle \cos\alpha= \frac{2\sqrt{10}}{11}