Kąt α jest ostry i cosα=5/13. Oblicz wartość wyrażenia sinα⋅tgα.

$\displaystyle \frac{144}{65}$\displaystyle \frac{144}{65}

$\displaystyle \frac{13}{5}$\displaystyle \frac{13}{5}

$\displaystyle \frac{12}{13}$\displaystyle \frac{12}{13}

$\displaystyle \frac{65}{144}$\displaystyle \frac{65}{144}