Kąt α jest ostry i sinα= 7/13. Wtedy tgα jest równy

$\displaystyle \frac{7}{6}$\displaystyle \frac{7}{6}

$\displaystyle \frac{7 \cdot 13}{120}$\displaystyle \frac{7 \cdot 13}{120}

$\displaystyle \frac{7}{\sqrt{120}}$\displaystyle \frac{7}{\sqrt{120}}

$\displaystyle \frac{7}{13\sqrt{120}}$\displaystyle \frac{7}{13\sqrt{120}}