Kąt α jest ostry i cosα= 3/5. Wtedy

$\displaystyle \sin\alpha \cdot \tg\alpha= \frac{16}{15}$\displaystyle \sin\alpha \cdot \tg\alpha= \frac{16}{15}

$\displaystyle \sin\alpha \cdot \tg\alpha= \frac{15}{16}$\displaystyle \sin\alpha \cdot \tg\alpha= \frac{15}{16}

$\displaystyle \sin\alpha \cdot \tg\alpha= \frac{8}{15}$\displaystyle \sin\alpha \cdot \tg\alpha= \frac{8}{15}

$\displaystyle \sin\alpha \cdot \tg\alpha= \frac{6}{20}$\displaystyle \sin\alpha \cdot \tg\alpha= \frac{6}{20}