Kąt α jest ostry i cosα= 3/7. Wtedy

$\displaystyle \sin\alpha= \frac{2\sqrt{10}}{7}$\displaystyle \sin\alpha= \frac{2\sqrt{10}}{7}

$\displaystyle \sin\alpha= \frac{\sqrt{10}}{7}$\displaystyle \sin\alpha= \frac{\sqrt{10}}{7}

$\displaystyle \sin\alpha= \frac{4}{7}$\displaystyle \sin\alpha= \frac{4}{7}

$\displaystyle \sin\alpha= \frac{3}{4}$\displaystyle \sin\alpha= \frac{3}{4}