Granica _{x→ -3} (0{,}5x^2+3{,}5x+6)/(-x^2+2x+15) jest równa

$\displaystyle \left(- \frac{1}{8} \right)$\displaystyle \left(- \frac{1}{8} \right)

$\displaystyle \frac{1}{16}$\displaystyle \frac{1}{16}

$\displaystyle \left(- \frac{1}{16} \right)$\displaystyle \left(- \frac{1}{16} \right)

$\displaystyle \frac{7}{4}$\displaystyle \frac{7}{4}