Kąt α jest ostry i tgα= 2/3. Wtedy

$\displaystyle \sin\alpha= \frac{3\sqrt{13}}{26}$\displaystyle \sin\alpha= \frac{3\sqrt{13}}{26}

$\displaystyle \sin\alpha= \frac{\sqrt{13}}{13}$\displaystyle \sin\alpha= \frac{\sqrt{13}}{13}

$\displaystyle \sin\alpha= \frac{2\sqrt{13}}{13}$\displaystyle \sin\alpha= \frac{2\sqrt{13}}{13}

$\displaystyle \sin\alpha= \frac{3\sqrt{13}}{13}$\displaystyle \sin\alpha= \frac{3\sqrt{13}}{13}