Granica _{x 2} (x^3-8)/(2x^2+2x-12) jest równa

$\displaystyle \frac{2}{5}$\displaystyle \frac{2}{5}

$\displaystyle \frac{4}{5}$\displaystyle \frac{4}{5}

$\displaystyle \frac{6}{5}$\displaystyle \frac{6}{5}

$\displaystyle \frac{12}{5}$\displaystyle \frac{12}{5}